簡約 4(sin(2pirst^3))^2s^2

解

簡約

4 (sin (2 π rs t^{3}))^{2} s^{2}

4 s^{2} sin^{2} (2 π rs t^{3})

解答ステップ

4 (sin (2 π rs t^{3}))^{2} s^{2}

指数の規則を適用する:

a^{m} b^{m} = (ab)^{m},

, 以下を想定

a \geq 0, b \geq 0

s^{2} (sin (2 π rs t^{3}))^{2} = (s sin (2 π rs t^{3}))^{2}

= 4 (s sin (2 π rs t^{3}))^{2}

(sin (2 π rs t^{3}) s)^{2} = s^{2} sin^{2} (2 π rs t^{3})

= 4 s^{2} sin^{2} (2 π rs t^{3})