展开 ((b+2)(a+1))/2

解答

展开

\frac{( b + 2 ) ( a + 1 )}{2}

\frac{ba}{2} + \frac{b}{2} + a + 1

求解步骤

\frac{( b + 2 ) ( a + 1 )}{2}

乘开

(b + 2) (a + 1) : ba + b + 2 a + 2

= \frac{ba + b + 2 a + 2}{2}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{ba + b + 2 a + 2}{2} = \frac{ba}{2} + \frac{b}{2} + \frac{2 a}{2} + \frac{2}{2}

= \frac{ba}{2} + \frac{b}{2} + \frac{2 a}{2} + \frac{2}{2}

使用法则

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{ba}{2} + \frac{b}{2} + \frac{2 a}{2} + 1

数字相除:

\frac{2}{2} = 1

= \frac{ba}{2} + \frac{b}{2} + a + 1

e x p an d (ln (x + 0.3) - (3 2 x - 5))^{2}

e x p an d, (\frac{2}{3} x + \frac{2}{3}) (\frac{4 y}{3} + \frac{1}{3})

e x p an d (\frac{16 - a}{2})^{2}

e x p an d (a \cdot b^{'} + c) (a + b)

e x p an d \frac{3}{2} (y = 1)^{2} - 3 y (y + 1)