展开 (ln(x+0.3)-(\sqrt[3]{2x-5}))^2

解答

展开

(ln (x + 0.3) - (3 2 x - 5))^{2}

ln^{2} (x + 0.3) - 2 ln (x + 0.3) 3 2 x - 5 + (2 x - 5)^{\frac{2}{3}}

求解步骤

(ln (x + 0.3) - (3 2 x - 5))^{2}

去除括号:

(a) = a

= (ln (x + 0.3) - 3 2 x - 5)^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = ln (x + 0.3), b = 3 2 x - 5

= ln^{2} (x + 0.3) - 2 ln (x + 0.3) 3 2 x - 5 + (3 2 x - 5)^{2}

(3 2 x - 5)^{2} = (2 x - 5)^{\frac{2}{3}}

= ln^{2} (x + 0.3) - 2 ln (x + 0.3) 3 2 x - 5 + (2 x - 5)^{\frac{2}{3}}

e x p an d, (\frac{2}{3} x + \frac{2}{3}) (\frac{4 y}{3} + \frac{1}{3})

e x p an d (\frac{16 - a}{2})^{2}

e x p an d (a \cdot b^{'} + c) (a + b)

e x p an d \frac{3}{2} (y = 1)^{2} - 3 y (y + 1)

e x p an d \frac{x ^{2} - 1}{( 1 + x ^{2} ) ^{2}}