展开 (10z+2)/((z+1)^2(z-3)^2)

解答

展开

\frac{10 z + 2}{( z + 1 ) ^{2} ( z - 3 ) ^{2}}

\frac{10 z + 2}{z ^{4} - 4 z ^{3} - 2 z ^{2} + 12 z + 9}

求解步骤

\frac{10 z + 2}{( z + 1 ) ^{2} ( z - 3 ) ^{2}}

(z + 1)^{2} = z^{2} + 2 z + 1

= \frac{10 z + 2}{( z ^{2} + 2 z + 1 ) ( z - 3 ) ^{2}}

(z - 3)^{2} = z^{2} - 6 z + 9

= \frac{10 z + 2}{( z ^{2} + 2 z + 1 ) ( z ^{2} - 6 z + 9 )}

乘开

(z^{2} + 2 z + 1) (z^{2} - 6 z + 9) : z^{4} - 4 z^{3} - 2 z^{2} + 12 z + 9

= \frac{10 z + 2}{z ^{4} - 4 z ^{3} - 2 z ^{2} + 12 z + 9}

e x p an d \frac{k}{( s ( s + 2 ) + k ^{2} + k )}

e x p an d lo g_{4} (\frac{b ^{3}}{b + 7})

e x p an d \frac{u ^{2} + 6 u + 9}{u}

e x p an d e^{2 (t - 2)} cos (w) (t - 2) H (t - 2)

e x p an d \frac{( ( 3 a ^{2} b ^{3} - 7 x ^{2} y ) ^{5} - 1 )}{3 a ^{2} b ^{3} - 7 x ^{2} y}