展开 e^{2(t-2)}cos(w)(t-2)\H(t-2)

解答

展开

e^{2 (t - 2)} cos (w) (t - 2) H (t - 2)

e^{2 t - 4} t H (t - 2) cos (w) - 2 e^{2 t - 4} H (t - 2) cos (w)

求解步骤

e^{2 (t - 2)} cos (w) (t - 2) H (t - 2)

= e^{2 (t - 2)} H (t - 2) cos (w) (t - 2)

使用分配律:

a (b - c) = ab - a c

a = e^{2 (t - 2)} cos (w) H (t - 2), b = t, c = 2

= e^{2 (t - 2)} cos (w) H (t - 2) t - e^{2 (t - 2)} cos (w) H (t - 2) \cdot 2

= e^{2 (t - 2)} t H (t - 2) cos (w) - 2 e^{2 (t - 2)} H (t - 2) cos (w)

化简

e^{2 (t - 2)} t H (t - 2) cos (w) - 2 e^{2 (t - 2)} H (t - 2) cos (w) : e^{2 t - 4} t H (t - 2) cos (w) - 2 e^{2 t - 4} H (t - 2) cos (w)

= e^{2 t - 4} t H (t - 2) cos (w) - 2 e^{2 t - 4} H (t - 2) cos (w)

e x p an d \frac{( ( 3 a ^{2} b ^{3} - 7 x ^{2} y ) ^{5} - 1 )}{3 a ^{2} b ^{3} - 7 x ^{2} y}

\frac{d}{d y} ((x) (2 y^{3} + x - π^{7} - 4 x^{3} + cos (3 + 2 y) - 5))

e x p an d e^{(5 t - 10)} h (t - 2)

e x p an d s + 5 ((s + 6) (s + 3))

s im pl i f y 3 x^{4} (- 4 - \cdot 4) + x^{0} - (- 7)