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受欢迎的代数 >

-10q+1000=0.12q^2+200

解答

- 10 q + 1000 = 0.12 q^{2} + 200

解答

q = 50, q = - \frac{400}{3}

+1

十进制

q = 50, q = - 133.33333 \dots

求解步骤

- 10 q + 1000 = 0.12 q^{2} + 200

在两边乘以

100

- 1000 q + 100000 = 12 q^{2} + 20000

交换两边

12 q^{2} + 20000 = - 1000 q + 100000

将

100000

para o lado esquerdo

12 q^{2} - 80000 = - 1000 q

将

1000 q

para o lado esquerdo

12 q^{2} - 80000 + 1000 q = 0

改写成标准形式

a x^{2} + b x + c = 0

12 q^{2} + 1000 q - 80000 = 0

使用求根公式求解

q_{1, 2} = \frac{- 1000 \pm 100 0 ^{2} - 4 \cdot 12 ( - 80000 )}{2 \cdot 12}

100 0^{2} - 4 \cdot 12 (- 80000) = 2200

q_{1, 2} = \frac{- 1000 \pm 2200}{2 \cdot 12}

将解分隔开

q_{1} = \frac{- 1000 + 2200}{2 \cdot 12}, q_{2} = \frac{- 1000 - 2200}{2 \cdot 12}

q = \frac{- 1000 + 2200}{2 \cdot 12} : 50

q = \frac{- 1000 - 2200}{2 \cdot 12} : - \frac{400}{3}

二次方程组的解是:

q = 50, q = - \frac{400}{3}

作图

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