化简-(2+i-ti)^2i

解答

化简

- (2 + i - t i)^{2} i

(4 - 4 t) + (t^{2} - 2 t - 3) i

求解步骤

- (2 + i - t i)^{2} i

展开

(2 + i - t i)^{2} : 4 i - t^{2} - 4 t i + 2 t + 3

= - (4 i - t^{2} - 4 t i + 2 t + 3) i

= - i (4 i - t^{2} - 4 t i + 2 t + 3)

打开括号

= - i 4 i - i (- t^{2}) - i (- 4 t i) - i 2 t - i 3

化简

- i 4 i - i (- t^{2}) - i (- 4 t i) - i 2 t - i 3 : 4 + t^{2} i - 4 t - 2 t i - 3 i

= 4 + t^{2} i - 4 t - 2 t i - 3 i

Rewrite in standard complex form:

(4 - 4 t) + (t^{2} - 2 t - 3) i

= (4 - 4 t) + (t^{2} - 2 t - 3) i

e x p an d \frac{( 2 x + 1 ) 3 x}{2}

e x p an d (2 e^{x} - 2 e^{- x})^{3}

e x p an d e^{t x} \cdot (e^{t} - 1)

e x p an d z^{3} e^{z} - 3 (z^{2} e^{z} - 2 (e^{z} z - e^{z})) + C

e x p an d 6.16 + 0.22 e^{- e^{0.65} (x - 1.22)}