Using a Problem-Solving Strategy to Solve Number Problems
Learning Outcomes
- Solve number problems
- Solve consecutive integer problems
Solving Number Problems
Now we will translate and solve number problems. In number problems, you are given some clues about one or more numbers, and you use these clues to build an equation. Number problems don't usually arise on an everyday basis, but they provide a good introduction to practicing the Problem-Solving Strategy. Remember to look for clue words such as difference, of, and and.Example
The difference of a number and six is thirteen. Find the number. Solution:Step 1. Read the problem. Do you understand all the words? | |
Step 2. Identify what you are looking for. | the number |
Step 3. Name. Choose a variable to represent the number. | Let [latex]n=\text{the number}[/latex] |
Step 4. Translate. Restate as one sentence. Translate into an equation. | [latex]n-6\enspace\Rightarrow[/latex] The difference of a number and 6 [latex]=\enspace\Rightarrow[/latex] is [latex]13\enspace\Rightarrow[/latex] thirteen |
Step 5. Solve the equation. Add 6 to both sides. Simplify. | [latex]n-6=13[/latex] [latex-display]n-6\color{red}{+6}=13\color{red}{+6}[/latex-display] [latex]n=19[/latex] |
Step 6. Check:The difference of [latex]19[/latex] and [latex]6[/latex] is [latex]13[/latex]. It checks. | |
Step 7. Answer the question. | The number is [latex]19[/latex]. |
try it
[embed]example
The sum of twice a number and seven is fifteen. Find the number.Answer:
Solution:Step 1. Read the problem. | |
Step 2. Identify what you are looking for. | the number |
Step 3. Name. Choose a variable to represent the number. | Let [latex]n=\text{the number}[/latex] |
Step 4. Translate. Restate the problem as one sentence. Translate into an equation. | [latex]2n\enspace\Rightarrow[/latex] The sum of twice a number [latex]+\enspace\Rightarrow[/latex] and [latex]7\enspace\Rightarrow[/latex] seven [latex]=\enspace\Rightarrow[/latex] is [latex]15\enspace\Rightarrow[/latex] fifteen |
Step 5. Solve the equation. | [latex]2n+7=15[/latex] |
Subtract 7 from each side and simplify. | [latex]2n=8[/latex] |
Divide each side by 2 and simplify. | [latex]n=4[/latex] |
Step 6. Check: is the sum of twice [latex]4[/latex] and [latex]7[/latex] equal to [latex]15[/latex]? | [latex]2\cdot{4}+7=15[/latex] [latex-display]8+7=15[/latex-display] [latex]15=15\quad\checkmark[/latex] |
Step 7. Answer the question. | The number is [latex]4[/latex]. |
try it
[embed]Solving for Two or More Numbers
Some number word problems ask you to find two or more numbers. It may be tempting to name them all with different variables, but so far we have only solved equations with one variable. We will define the numbers in terms of the same variable. Be sure to read the problem carefully to discover how all the numbers relate to each other.example
One number is five more than another. The sum of the numbers is twenty-one. Find the numbers.Answer:
Solution:Step 1. Read the problem. | ||
Step 2. Identify what you are looking for. | You are looking for two numbers. | |
Step 3. Name.Choose a variable to represent the first number. What do you know about the second number? Translate. | Let [latex]n=\text{1st number}[/latex]One number is five more than another. [latex]n+5={2}^{\text{nd}}\text{number}[/latex] | |
Step 4. Translate.Restate the problem as one sentence with all the important information. Translate into an equation. Substitute the variable expressions. | The sum of the numbers is [latex]21[/latex].The sum of the 1st number and the 2nd number is [latex]21[/latex]. [latex]n\enspace\Rightarrow[/latex] First number [latex]+\enspace\Rightarrow[/latex] + [latex]n+5\enspace\Rightarrow[/latex] Second number [latex]=\enspace\Rightarrow[/latex] = [latex]21\enspace\Rightarrow[/latex] twenty-one | |
Step 5. Solve the equation. | [latex]n+n+5=21[/latex] | |
Combine like terms. | [latex]2n+5=21[/latex] | |
Subtract five from both sides and simplify. | [latex]2n=16[/latex] | |
Divide by two and simplify. | [latex]n=8[/latex] 1st number | |
Now find the second number. | [latex]n+5[/latex] 2nd number | |
Substitute [latex]n = 8[/latex] | [latex]\color{red}{8}+5[/latex] | |
[latex]13[/latex] | ||
Step 6. Check: | ||
Do these numbers check in the problem?Is one number 5 more than the other? Is thirteen, 5 more than 8? Yes. Is the sum of the two numbers 21? | [latex]13\stackrel{\text{?}}{=}8+5[/latex][latex]13=13\quad\checkmark[/latex] [latex-display]8+13\stackrel{\text{?}}{=}21[/latex-display] [latex]21=21\quad\checkmark[/latex] | |
Step 7. Answer the question. | The numbers are [latex]8[/latex] and [latex]13[/latex]. |
try it
[embed]example
The sum of two numbers is negative fourteen. One number is four less than the other. Find the numbers.Answer:
Solution:Step 1. Read the problem. | ||
Step 2. Identify what you are looking for. | two numbers | |
Step 3. Name. Choose a variable.What do you know about the second number? Translate. | Let [latex]n=\text{1st number}[/latex]One number is [latex]4[/latex] less than the other. [latex]n-4={2}^{\text{nd}}\text{number}[/latex] | |
Step 4. Translate.Write as one sentence. Translate into an equation. Substitute the variable expressions. | The sum of two numbers is negative fourteen.[latex]n\enspace\Rightarrow[/latex] First number [latex]+\enspace\Rightarrow[/latex] + [latex]n-4\enspace\Rightarrow[/latex] Second number [latex]=\enspace\Rightarrow[/latex] = [latex]-14\enspace\Rightarrow[/latex] negative fourteen | |
Step 5. Solve the equation. | [latex]n+n-4=-14[/latex] | |
Combine like terms. | [latex]2n-4=-14[/latex] | |
Add 4 to each side and simplify. | [latex]2n=-10[/latex] | |
Divide by 2. | [latex]n=-5[/latex] 1st number | |
Substitute [latex]n=-5[/latex] to find the 2^{nd} number. | [latex]n-4[/latex] 2nd number | |
[latex]\color{red}{-5}-4[/latex] | ||
[latex]-9[/latex] | ||
Step 6. Check: | ||
Is −9 four less than −5?Is their sum −14? | [latex]-5-4\stackrel{\text{?}}{=}-9[/latex][latex]-9=-9\quad\checkmark[/latex] [latex-display]-5+(-9)\stackrel{\text{?}}{=}-14[/latex-display] [latex]-14=-14\quad\checkmark[/latex] | |
Step 7. Answer the question. | The numbers are [latex]−5[/latex] and [latex]−9[/latex]. |
try it
[embed]example
One number is ten more than twice another. Their sum is one. Find the numbers.Answer:
Solution:Step 1. Read the problem. | ||
Step 2. Identify what you are looking for. | two numbers | |
Step 3. Name. Choose a variable.One number is ten more than twice another. | Let [latex]x=\text{1st number}[/latex][latex]2x+10={2}^{\text{nd}}\text{number}[/latex] | |
Step 4. Translate. Restate as one sentence. | Their sum is one. | |
Translate into an equation | [latex]x+(2x+10)\enspace\Rightarrow[/latex] The sum of the two numbers[latex]=\enspace\Rightarrow[/latex] is [latex]1\enspace\Rightarrow[/latex] one | |
Step 5. Solve the equation. | [latex]x+2x+10=1[/latex] | |
Combine like terms. | [latex]3x+10=1[/latex] | |
Subtract 10 from each side. | [latex]3x=-9[/latex] | |
Divide each side by 3 to get the first number. | [latex]x=-3[/latex] | |
Substitute to get the second number. | [latex]2x+10[/latex] | |
[latex]2(\color{red}{-3})+10[/latex] | ||
[latex]4[/latex] | ||
Step 6. Check. | ||
Is 4 ten more than twice −3?Is their sum 1? | [latex]2(-3)+10\stackrel{\text{?}}{=}4[/latex][latex]-6+10=4[/latex] [latex-display]4=4\quad\checkmark[/latex-display] [latex-display]-3+4\stackrel{\text{?}}{=}1[/latex-display] [latex]1=1\quad\checkmark[/latex] | |
Step 7. Answer the question. | The numbers are [latex]−3[/latex] and [latex]4[/latex]. |
try it
[embed]Solving for Consecutive Integers
Another type of number problem involves consecutive numbers. Consecutive numbers are numbers that come one after the other. Some examples of consecutive integers are:[latex]\begin{array}{c} \hfill \text{...}1, 2, 3, 4, 5, 6\text{,...}\hfill \end{array}[/latex] [latex-display]\text{...}-10,-9,-8,-7\text{,...}[/latex-display] [latex]\text{...}150,151,152,153\text{,...}[/latex]
If we are looking for several consecutive numbers, it is important to first identify what they look like with variables before we set up the equation. Notice that each number is one more than the number preceding it. So if we define the first integer as [latex]n[/latex], the next consecutive integer is [latex]n+1[/latex]. The one after that is one more than [latex]n+1[/latex], so it is [latex]n+1+1[/latex], or [latex]n+2[/latex].[latex]\begin{array}{cccc}n\hfill & & & \text{1st integer}\hfill \\ n+1\hfill & & & \text{2nd consecutive integer}\hfill \\ n+2\hfill & & & \text{3rd consecutive integer}\hfill \end{array}[/latex]
For example, let's say I want to know the next consecutive integer after [latex]4[/latex]. In mathematical terms, we would add [latex]1[/latex] to [latex]4[/latex] to get [latex]5[/latex]. We can generalize this idea as follows: the consecutive integer of any number, [latex]x[/latex], is [latex]x+1[/latex]. If we continue this pattern, we can define any number of consecutive integers from any starting point. The following table shows how to describe four consecutive integers using algebraic notation.First | [latex]x[/latex] |
Second | [latex]x+1[/latex] |
Third | [latex]x+2[/latex] |
Fourth | [latex]x+3[/latex] |
example
The sum of two consecutive integers is [latex]47[/latex]. Find the numbers. Solution:Step 1. Read the problem. | ||
Step 2. Identify what you are looking for. | two consecutive integers | |
Step 3. Name. | Let [latex]n=\text{1st integer}[/latex] [latex]n+1=\text{next consecutive integer}[/latex] | |
Step 4. Translate. Restate as one sentence. Translate into an equation. | [latex]n+n+1\enspace\Rightarrow[/latex] The sum of the integers [latex]=\enspace\Rightarrow[/latex] is [latex]47\enspace\Rightarrow[/latex] 47 | |
Step 5. Solve the equation. | [latex]n+n+1=47[/latex] | |
Combine like terms. | [latex]2n+1=47[/latex] | |
Subtract 1 from each side. | [latex]2n=46[/latex] | |
Divide each side by 2. | [latex]n=23[/latex] 1st integer | |
Substitute to get the second number. | [latex]n+1[/latex] 2nd integer | |
[latex]\color{red}{23}+1[/latex] | ||
[latex]24[/latex] | ||
Step 6. Check: | [latex]23+24\stackrel{\text{?}}{=}47[/latex] [latex]47=47\quad\checkmark[/latex] | |
Step 7. Answer the question. | The two consecutive integers are [latex]23[/latex] and [latex]24[/latex]. |
try it
[ohm_question]142817[/ohm_question]Example
The sum of three consecutive integers is [latex]93[/latex]. What are the integers?Answer: Following the steps provided:
- Read and understand: We are looking for three numbers, and we know they are consecutive integers.
- Constants and Variables: [latex]93[/latex] is a constant. The first integer we will call [latex]x[/latex]. Second integer: [latex]x+1[/latex] Third integer: [latex]x+2[/latex]
- Translate: The sum of three consecutive integers translates to [latex]x+\left(x+1\right)+\left(x+2\right)[/latex], based on how we defined the first, second, and third integers. Notice how we placed parentheses around the second and third integers. This is just to make each integer more distinct. "is 93" translates to "[latex]=93[/latex]" since "is" is associated with equals.
- Write an equation: [latex]x+\left(x+1\right)+\left(x+2\right)=93[/latex]
- Solve the equation using what you know about solving linear equations: We can't simplify within each set of parentheses, and we don't need to use the distributive property so we can rewrite the equation without parentheses.
[latex]x+x+1+x+2=93[/latex]
Combine like terms, simplify, and solve.[latex]\begin{array}{r}x+x+1+x+2=93\\3x+3 = 93\\\underline{-3\,\,\,\,\,-3}\\3x=90\\\frac{3x}{3}=\frac{90}{3}\\x=30\end{array}[/latex]
- Check and Interpret: Okay, we have found a value for [latex]x[/latex]. We were asked to find the value of three consecutive integers, so we need to do a couple more steps. Remember how we defined our variables:
The first integer we will call [latex]x[/latex], [latex]x=30[/latex] Second integer: [latex]x+1[/latex] so [latex]30+1=31[/latex] Third integer: [latex]x+2[/latex] so [latex]30+2=32[/latex] The three consecutive integers whose sum is [latex]93[/latex] are [latex]30\text{, }31\text{, and }32[/latex]
example
Find three consecutive integers whose sum is [latex]42[/latex].Answer:
Solution:Step 1. Read the problem. | ||
Step 2. Identify what you are looking for. | three consecutive integers | |
Step 3. Name. | Let [latex]n=\text{1st integer}[/latex][latex]n+1=\text{2nd consecutive integer}[/latex] [latex-display]n+2=\text{3rd consecutive integer}[/latex-display] | |
Step 4. Translate. Restate as one sentence. Translate into an equation. | [latex]n\enspace +\enspace n+1\enspace +\enspace n+2\enspace\Rightarrow[/latex] The sum of the three integers [latex]=\enspace\Rightarrow[/latex] is [latex]42\enspace\Rightarrow[/latex] 42 | |
Step 5. Solve the equation. | [latex]n+n+1+n+2=42[/latex] | |
Combine like terms. | [latex]3n+3=42[/latex] | |
Subtract 3 from each side. | [latex]3n=39[/latex] | |
Divide each side by 3. | [latex]n=13[/latex] 1st integer | |
Substitute to get the second number. | [latex]n+1[/latex] 2nd integer | |
[latex]\color{red}{13}+1[/latex] | ||
[latex]24[/latex] | ||
Substitute to get the third number. | [latex]n+2[/latex] 3rd integer | |
[latex]\color{red}{13}+2[/latex] | ||
[latex]15[/latex] | ||
Step 6. Check: | [latex]13+14+15\stackrel{\text{?}}{=}42[/latex][latex]42=42\quad\checkmark[/latex] | |
Step 7. Answer the question. | The three consecutive integers are [latex]13[/latex], [latex]14[/latex], and [latex]15[/latex]. |
try it
[ohm_question]142816[/ohm_question]Contribute!
Licenses & Attributions
CC licensed content, Shared previously
- Ex: Linear Equation Application with One Variable - Number Problem. Authored by: James Sousa (Mathispower4u.com). License: CC BY: Attribution.
- Ex: Write and Solve an Equation for Consecutive Natural Numbers with a Given Sum. Authored by: James Sousa (Mathispower4u.com). License: CC BY: Attribution.
- Write and Solve a Linear Equations to Solve a Number Problem (1) Mathispower4u . Authored by: James Sousa (Mathispower4u.com) for Lumen Learning. License: CC BY: Attribution.
- Question ID 142763, 142770, 142775, 142806, 142811, 142816, 142817. Authored by: Lumen Learning. License: CC BY: Attribution. License terms: IMathAS Community License, CC-BY + GPL.
CC licensed content, Specific attribution
- Prealgebra. Provided by: OpenStax License: CC BY: Attribution. License terms: Download for free at http://cnx.org/contents/[email protected].