cos(x)=(sqrt(3))/3 ,0<= x<= 2pi

解

cos (x) = \frac{3}{3}, 0 \leq x \leq 2 π

x = 0.95531 \dots, x = 2 π - 0.95531 \dots

度

x = 54.73561 \dots^{\circ}, x = 305.26438 \dots^{\circ}

解答ステップ

cos (x) = \frac{3}{3}, 0 \leq x \leq 2 π

三角関数の逆数プロパティを適用する

cos (x) = \frac{3}{3}

以下の一般解

cos (x) = \frac{3}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{3}{3}) + 2 πn, x = 2 π - arccos (\frac{3}{3}) + 2 πn

x = arccos (\frac{3}{3}) + 2 πn, x = 2 π - arccos (\frac{3}{3}) + 2 πn

範囲の解答

0 \leq x \leq 2 π

x = arccos (\frac{3}{3}), x = 2 π - arccos (\frac{3}{3})

10進法形式で解を証明する

x = 0.95531 \dots, x = 2 π - 0.95531 \dots