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人気のある三角関数 >

sec^2(x)=2tan^2(x)

解

sec^{2} (x) = 2 tan^{2} (x)

解

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn, x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

+1

度

x = 22 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n, x = 4 5^{\circ} + 36 0^{\circ} n, x = 13 5^{\circ} + 36 0^{\circ} n

解答ステップ

sec^{2} (x) = 2 tan^{2} (x)

両辺から

2 tan^{2} (x)

を引く

sec^{2} (x) - 2 tan^{2} (x) = 0

因数

sec^{2} (x) - 2 tan^{2} (x) : (sec (x) + 2 tan (x)) (sec (x) - 2 tan (x))

sec^{2} (x) - 2 tan^{2} (x)

sec^{2} (x) - 2 tan^{2} (x)

を書き換え

sec^{2} (x) - (2 tan (x))^{2}

sec^{2} (x) - 2 tan^{2} (x)

累乗根の規則を適用する:

a = (a)^{2}

2 = (2)^{2}

= sec^{2} (x) - (2)^{2} tan^{2} (x)

指数の規則を適用する:

a^{m} b^{m} = (ab)^{m}

(2)^{2} tan^{2} (x) = (2 tan (x))^{2}

= sec^{2} (x) - (2 tan (x))^{2}

= sec^{2} (x) - (2 tan (x))^{2}

2乗の差の公式を適用する:

x^{2} - y^{2} = (x + y) (x - y)

sec^{2} (x) - (2 tan (x))^{2} = (sec (x) + 2 tan (x)) (sec (x) - 2 tan (x))

= (sec (x) + 2 tan (x)) (sec (x) - 2 tan (x))

(sec (x) + 2 tan (x)) (sec (x) - 2 tan (x)) = 0

各部分を別個に解く

sec (x) + 2 tan (x) = 0 or sec (x) - 2 tan (x) = 0

sec (x) + 2 tan (x) = 0 : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

sec (x) + 2 tan (x) = 0

サイン, コサインで表わす

sec (x) + 2 tan (x)

基本的な三角関数の公式を使用する:

sec (x) = \frac{1}{cos ( x )}

= \frac{1}{cos ( x )} + 2 tan (x)

基本的な三角関数の公式を使用する:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{1}{cos ( x )} + 2 \frac{sin ( x )}{cos ( x )}

簡素化

\frac{1}{cos ( x )} + 2 \frac{sin ( x )}{cos ( x )} : \frac{1 + 2 sin ( x )}{cos ( x )}

\frac{1}{cos ( x )} + 2 \frac{sin ( x )}{cos ( x )}

乗じる

2 \frac{sin ( x )}{cos ( x )} : \frac{2 sin ( x )}{cos ( x )}

2 \frac{sin ( x )}{cos ( x )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) 2}{cos ( x )}

= \frac{1}{cos ( x )} + \frac{2 sin ( x )}{cos ( x )}

規則を適用

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 2 sin ( x )}{cos ( x )}

= \frac{1 + 2 sin ( x )}{cos ( x )}

\frac{1 + sin ( x ) 2}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 + sin (x) 2 = 0

1

を右側に移動します

1 + sin (x) 2 = 0

両辺から

1

を引く

1 + sin (x) 2 - 1 = 0 - 1

簡素化

sin (x) 2 = - 1

sin (x) 2 = - 1

以下で両辺を割る

2

sin (x) 2 = - 1

以下で両辺を割る

2

\frac{sin ( x ) 2}{2} = \frac{- 1}{2}

簡素化

\frac{sin ( x ) 2}{2} = \frac{- 1}{2}

簡素化

\frac{sin ( x ) 2}{2} : sin (x)

\frac{sin ( x ) 2}{2}

共通因数を約分する:

2

= sin (x)

簡素化

\frac{- 1}{2} : - \frac{2}{2}

\frac{- 1}{2}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

有理化する

- \frac{1}{2} : - \frac{2}{2}

- \frac{1}{2}

共役で乗じる

\frac{2}{2}

= - \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

累乗根の規則を適用する:

a a = a

22 = 2

= 2

= - \frac{2}{2}

= - \frac{2}{2}

sin (x) = - \frac{2}{2}

sin (x) = - \frac{2}{2}

sin (x) = - \frac{2}{2}

以下の一般解

sin (x) = - \frac{2}{2}

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

sec (x) - 2 tan (x) = 0 : x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

sec (x) - 2 tan (x) = 0

サイン, コサインで表わす

sec (x) - 2 tan (x)

基本的な三角関数の公式を使用する:

sec (x) = \frac{1}{cos ( x )}

= \frac{1}{cos ( x )} - 2 tan (x)

基本的な三角関数の公式を使用する:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{1}{cos ( x )} - 2 \frac{sin ( x )}{cos ( x )}

簡素化

\frac{1}{cos ( x )} - 2 \frac{sin ( x )}{cos ( x )} : \frac{1 - 2 sin ( x )}{cos ( x )}

\frac{1}{cos ( x )} - 2 \frac{sin ( x )}{cos ( x )}

乗じる

2 \frac{sin ( x )}{cos ( x )} : \frac{2 sin ( x )}{cos ( x )}

2 \frac{sin ( x )}{cos ( x )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) 2}{cos ( x )}

= \frac{1}{cos ( x )} - \frac{2 sin ( x )}{cos ( x )}

規則を適用

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 - 2 sin ( x )}{cos ( x )}

= \frac{1 - 2 sin ( x )}{cos ( x )}

\frac{1 - sin ( x ) 2}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 - sin (x) 2 = 0

1

を右側に移動します

1 - sin (x) 2 = 0

両辺から

1

を引く

1 - sin (x) 2 - 1 = 0 - 1

簡素化

- sin (x) 2 = - 1

- sin (x) 2 = - 1

以下で両辺を割る

- 2

- sin (x) 2 = - 1

以下で両辺を割る

- 2

\frac{- sin ( x ) 2}{- 2} = \frac{- 1}{- 2}

簡素化

\frac{- sin ( x ) 2}{- 2} = \frac{- 1}{- 2}

簡素化

\frac{- sin ( x ) 2}{- 2} : sin (x)

\frac{- sin ( x ) 2}{- 2}

分数の規則を適用する:

\frac{- a}{- b} = \frac{a}{b}

= \frac{sin ( x ) 2}{2}

共通因数を約分する:

2

= sin (x)

簡素化

\frac{- 1}{- 2} : \frac{2}{2}

\frac{- 1}{- 2}

分数の規則を適用する:

\frac{- a}{- b} = \frac{a}{b}

= \frac{1}{2}

有理化する

\frac{1}{2} : \frac{2}{2}

\frac{1}{2}

共役で乗じる

\frac{2}{2}

= \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

累乗根の規則を適用する:

a a = a

22 = 2

= 2

= \frac{2}{2}

= \frac{2}{2}

sin (x) = \frac{2}{2}

sin (x) = \frac{2}{2}

sin (x) = \frac{2}{2}

以下の一般解

sin (x) = \frac{2}{2}

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

すべての解を組み合わせる

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn, x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

グラフ

人気の例

(sin(x))/(cos(x))-5+(4cos(x))/(sin(x))=0

\frac{sin ( x )}{cos ( x )} - 5 + \frac{4 cos ( x )}{sin ( x )} = 0

solvefor x,y=sin(3.2x)

so l v e f or x, y = sin (3.2 x)

sin(x)=0.37,pi<x< pi/2

sin (x) = 0.37, π < x < \frac{π}{2}

5cot(x)+3tan(x)=8

5 cot (x) + 3 tan (x) = 8

sin(2x)-1=cos(2x),\forall 0<= θ<2pi

sin (2 x) - 1 = cos (2 x), \forall 0 \leq θ < 2 π