cos(α)=(sqrt(3))/2

Lösung

cos (α) = \frac{3}{2}

α = \frac{π}{6} + 2 πn, α = \frac{11 π}{6} + 2 πn

Grad

α = 3 0^{\circ} + 36 0^{\circ} n, α = 33 0^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (α) = \frac{3}{2}

Allgemeine Lösung für

cos (α) = \frac{3}{2}

cos (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

α = \frac{π}{6} + 2 πn, α = \frac{11 π}{6} + 2 πn

α = \frac{π}{6} + 2 πn, α = \frac{11 π}{6} + 2 πn

tan (t) = - \frac{4}{3}

sin^{2} (x) = 0.25

sin (x) + 3 cos (x) = 3

\frac{sin ( 2 x )}{4 sin ( 2 x ) - 1} = 1

2 cos (θ) sin (θ) = sin (θ)