sin(39)+sin(21)=sin(a)

Lösung

sin (3 9^{\circ}) + sin (2 1^{\circ}) = sin (a^{\circ})

Keine L \overset{o}{¨} sung f \overset{u}{¨} r a \in R

Schritte zur Lösung

sin (3 9^{\circ}) + sin (2 1^{\circ}) = sin (a^{\circ})

Tausche die Seiten

sin (a^{\circ}) = sin (3 9^{\circ}) + sin (2 1^{\circ})

Wende die Eigenschaften der Trigonometrie an

sin (a^{\circ}) = sin (3 9^{\circ}) + sin (2 1^{\circ})

Allgemeine Lösung für

sin (a^{\circ}) = sin (3 9^{\circ}) + sin (2 1^{\circ})

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

a^{\circ} = arcsin (sin (3 9^{\circ}) + sin (2 1^{\circ})) + 36 0^{\circ} n, a^{\circ} = 18 0^{\circ} - arcsin (sin (3 9^{\circ}) + sin (2 1^{\circ})) + 36 0^{\circ} n

a^{\circ} = arcsin (sin (3 9^{\circ}) + sin (2 1^{\circ})) + 36 0^{\circ} n, a^{\circ} = 18 0^{\circ} - arcsin (sin (3 9^{\circ}) + sin (2 1^{\circ})) + 36 0^{\circ} n

Keine L \overset{o}{¨} sung f \overset{u}{¨} r a \in R

arctan (4 x - 4) = - 1

tan^{2} (x + \frac{π}{6}) = 3

cos (θ) cos (2 θ) + sin (θ) sin (2 θ) = \frac{3}{2}

3 cos (2 x) - 2 cos (x) - 1 = 0

sin (3 π x) = 0