cos(θ)= 8/17 ,270<θ<360

Lösung

cos (θ) = \frac{8}{17}, 27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - 1.08083 \dots

Radianten

θ = 2 π - 1.08083 \dots

Schritte zur Lösung

cos (θ) = \frac{8}{17}, 27 0^{\circ} < θ < 36 0^{\circ}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{8}{17}

Allgemeine Lösung für

cos (θ) = \frac{8}{17}

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

θ = arccos (\frac{8}{17}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{8}{17}) + 36 0^{\circ} n

θ = arccos (\frac{8}{17}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{8}{17}) + 36 0^{\circ} n

Lösungen für den Bereich

27 0^{\circ} < θ < 36 0^{\circ}

θ = 36 0^{\circ} - arccos (\frac{8}{17})

Zeige Lösungen in Dezimalform

θ = 36 0^{\circ} - 1.08083 \dots

2 csc (θ) - 3 = 0

cos (x - \frac{π}{7}) = \frac{- 2}{2}, 0 \leq x \leq 2 π

sin (2 θ) = sin (θ)

25 cos^{2} (θ) - 1 = 0

cos (θ) = \frac{4}{7}