What is the asymptotes of f(x)=(3x^2+1)/(x^2+6x-7) ?

The asymptotes of f(x)=(3x^2+1)/(x^2+6x-7) is Vertical: x=-7,x=1,Horizontal: y=3

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asymptotes of f(x)=(3x^2+1)/(x^2+6x-7)

asymptotes

f (x) = \frac{3 x ^{2} + 1}{x ^{2} + 6 x - 7}

Vertical : x = - 7, x = 1, Horizontal : y = 3

Solution steps

Vertical asymptotes of

\frac{3 x ^{2} + 1}{x ^{2} + 6 x - 7} : x = - 7, x = 1

Horizontal Asymptotes of

\frac{3 x ^{2} + 1}{x ^{2} + 6 x - 7} : y = 3

Slant Asymptotes of

\frac{3 x ^{2} + 1}{x ^{2} + 6 x - 7} :

None

Vertical : x = - 7, x = 1, Horizontal : y = 3

f (x) = \frac{- 3 x ^{2}}{x ^{2} + 6 x - 40}

f (x) = \frac{x + 4}{x ^{2} + 4 x + 3}

f (x) = 2 - ln (x)

f (x) = - \frac{x}{25 - x ^{2}}

\frac{x ^{2}}{3 x + 2}

What is the asymptotes of f(x)=(3x^2+1)/(x^2+6x-7) ?
The asymptotes of f(x)=(3x^2+1)/(x^2+6x-7) is Vertical: x=-7,x=1,Horizontal: y=3