What is the asymptotes of f(x)=(-3x^2)/(x^2+6x-40) ?

The asymptotes of f(x)=(-3x^2)/(x^2+6x-40) is Vertical: x=-10,x=4,Horizontal: y=-3

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asymptotes of f(x)=(-3x^2)/(x^2+6x-40)

asymptotes

f (x) = \frac{- 3 x ^{2}}{x ^{2} + 6 x - 40}

Vertical : x = - 10, x = 4, Horizontal : y = - 3

Solution steps

Vertical asymptotes of

\frac{- 3 x ^{2}}{x ^{2} + 6 x - 40} : x = - 10, x = 4

Horizontal Asymptotes of

\frac{- 3 x ^{2}}{x ^{2} + 6 x - 40} : y = - 3

Slant Asymptotes of

\frac{- 3 x ^{2}}{x ^{2} + 6 x - 40} :

None

Vertical : x = - 10, x = 4, Horizontal : y = - 3

f (x) = \frac{x + 4}{x ^{2} + 4 x + 3}

f (x) = 2 - ln (x)

f (x) = - \frac{x}{25 - x ^{2}}

\frac{x ^{2}}{3 x + 2}

f (x) = \frac{x ^{3}}{2 x ^{3} - x ^{2} - 3 x}

What is the asymptotes of f(x)=(-3x^2)/(x^2+6x-40) ?
The asymptotes of f(x)=(-3x^2)/(x^2+6x-40) is Vertical: x=-10,x=4,Horizontal: y=-3