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Popular >

extreme f(x)=(4x^2)/(x^2-4)

Solution

extreme points

f (x) = \frac{4 x ^{2}}{x ^{2} - 4}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{32 x}{( x ^{2} - 4 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

\frac{4 x ^{2}}{x ^{2} - 4} : 0

Maximum (0, 0)

Popular Examples

extreme f(x)=x^2+2x+y^2 extreme points

f (x) = x^{2} + 2 x + y^{2}

extreme f(x,y)=4-x^2-y^2 extreme points

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extreme f(x)=x^2+4x extreme points

f (x) = x^{2} + 4 x

extreme f(x,y)=25*(y+x^2)^2+(1+x)^2 extreme points

f (x, y) = 25 \cdot (y + x^{2})^{2} + (1 + x)^{2}

extreme f(x)=sin^2(x)-sin(x)extreme points

f (x) = sin^{2} (x) - sin (x)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(4x^2)/(x^2-4) ?
The extreme f(x)=(4x^2)/(x^2-4) is Maximum(0,0)