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Popular >

extreme f(x)=x^2+4x

Solution

extreme points

f (x) = x^{2} + 4 x

Solution

Minimum (- 2, - 4)

Solution steps

f^{'} (x) = 2 x + 4

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

x^{2} + 4 x : - 4

Minimum (- 2, - 4)

Popular Examples

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f (x, y) = 25 \cdot (y + x^{2})^{2} + (1 + x)^{2}

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f (x) = 4 x^{3} + 9 x^{2} - 12 x + 7

extreme h(v,t)=vt-16t^2 extreme points

h (v, t) = v t - 16 t^{2}

extreme f(x)=-x^2-2x+3 extreme points

f (x) = - x^{2} - 2 x + 3

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+4x ?
The extreme f(x)=x^2+4x is Minimum(-2,-4)