What is the extreme f(x)=(5ln(x))/(x^3) ?

The extreme f(x)=(5ln(x))/(x^3) is Maximum(\sqrt[3]{e}, 5/(3e))

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extreme f(x)=(5ln(x))/(x^3)

extreme points

f (x) = \frac{5 ln ( x )}{x ^{3}}

Solution steps

f^{'} (x) = \frac{5 ( 1 - 3 ln ( x ) )}{x ^{4}}

Find intervals:

Increasing

Decreasing

Plug

into

\frac{5 ln ( x )}{x ^{3}} : \frac{5}{3 e}

f (x) = (x^{2} - 3 x + 5) e^{- \frac{x}{3}}

f (x) = x^{4} - 4 x^{3} + 16 x

f (x, y) = (6 - x) (6 - y) (x + y - 6)

f (x) = - x^{2} + 4

f (x) = x^{4} + y^{4} - 4 x y + 2

What is the extreme f(x)=(5ln(x))/(x^3) ?
The extreme f(x)=(5ln(x))/(x^3) is Maximum(\sqrt[3]{e}, 5/(3e))