What is the domain of f(x)=sqrt(x^2-7x+12) ?

The domain of f(x)=sqrt(x^2-7x+12) is x = 4

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domain of f(x)=sqrt(x^2-7x+12)

domain

f (x) = x^{2} - 7 x + 12

x \leq 3 or x \geq 4

Interval Notation

(- \infty, 3] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 3 or x \geq 4

The function domain

x \leq 3 or x \geq 4

f (x) = \frac{x + 4}{3 x ^{2} + 5 x + 2}

f (x) = 3 e^{x}

y = - x^{4} + 2 x^{2}

f (x) = lo g_{2} (x + 4)

5 x + 6

What is the domain of f(x)=sqrt(x^2-7x+12) ?
The domain of f(x)=sqrt(x^2-7x+12) is x<= 3\lor x>= 4