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Popular >

domain of f(x)=log_{b}(x^2+1)

Solution

domain

f (x) = lo g_{b} (x^{2} + 1)

Solution

0 < b < 1 or b > 1

+1

Solution steps

Check logs domain:

0 < b < 1 or b > 1

The function domain

0 < b < 1 or b > 1

Popular Examples

domain of f(x)= 1/(pi^x-1)domain

f (x) = \frac{1}{π ^{x} - 1}

domain of f(x)=(x^2+1)/(x^2+3)domain

f (x) = \frac{x ^{2} + 1}{x ^{2} + 3}

domain of f(x)= 1/(sqrt(6.5x-1.1x^2))domain

f (x) = \frac{1}{6.5 x - 1.1 x ^{2}}

domain of f(x)= x/((x-1)^2)domain

f (x) = \frac{x}{( x - 1 ) ^{2}}

domain of f(x)=((2x-1))/((x+1))domain

f (x) = \frac{( 2 x - 1 )}{( x + 1 )}

Frequently Asked Questions (FAQ)

What is the domain of f(x)=log_{b}(x^2+1) ?
The domain of f(x)=log_{b}(x^2+1) is 0<b<1\lor b>1