What is the domain of f(x)=(x^2+1)/(x^2+3) ?

The domain of f(x)=(x^2+1)/(x^2+3) is -infinity <x<infinity

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domain of f(x)=(x^2+1)/(x^2+3)

domain

f (x) = \frac{x ^{2} + 1}{x ^{2} + 3}

- \infty < x < \infty

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{1}{6.5 x - 1.1 x ^{2}}

f (x) = \frac{x}{( x - 1 ) ^{2}}

f (x) = \frac{( 2 x - 1 )}{( x + 1 )}

f (x) = x ∣ x ∣

f (x) = \frac{5}{x ^{2} + 2 x - 10}

What is the domain of f(x)=(x^2+1)/(x^2+3) ?
The domain of f(x)=(x^2+1)/(x^2+3) is -infinity <x<infinity