What is the inverse of f(x)=x^2-8x+10 ?

The inverse of f(x)=x^2-8x+10 is 4+sqrt(x+6),4-sqrt(x+6)

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inverse of f(x)=x^2-8x+10

inverse

f (x) = x^{2} - 8 x + 10

4 + x + 6, 4 - x + 6

Solution steps

y = x^{2} - 8 x + 10

Replace

x

with

y

x = y^{2} - 8 y + 10

Solve for

y, x = y^{2} - 8 y + 10

4 + x + 6, 4 - x + 6

a sy m pt o t es f (x) = x^{2} \cdot e^{- 2 x}

s hi f t - 5 cos (2 π x + 1)

a sy m pt o t es f (x) = \frac{( 2 x + 3 )}{( x )}

d o main - 4 t^{2} + 8

p er i o d i c i t y cos (x + \frac{π}{2})

What is the inverse of f(x)=x^2-8x+10 ?
The inverse of f(x)=x^2-8x+10 is 4+sqrt(x+6),4-sqrt(x+6)