What is the critical f(x)=(x+4)(x-2)^2 ?

The critical f(x)=(x+4)(x-2)^2 is x=-2,x=2

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critical f(x)=(x+4)(x-2)^2

critical points

f (x) = (x + 4) (x - 2)^{2}

x = - 2, x = 2

Solution steps

(x + 4) (x - 2)^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

(x + 4) (x - 2)^{2} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 2

(- 2, - 5), (- 9, 4)

x^{5}

f (x) = 13 x - 13

2 x + 2 y = 11

f (x) = 3 x + 12

What is the critical f(x)=(x+4)(x-2)^2 ?
The critical f(x)=(x+4)(x-2)^2 is x=-2,x=2