What is the domain of f(x)=5(x+4)^2-1 ?

The domain of f(x)=5(x+4)^2-1 is -infinity <x<infinity

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domain of f(x)=5(x+4)^2-1

domain

f (x) = 5 (x + 4)^{2} - 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

cr i t i c a l f (x) = x^{4} - 12 x^{3}

d o main f (x) = \frac{cos ( x )}{1 - sin ( x )}

m o n o t o n e 2 x^{2} - 3 x + 4

d o main f (x) = \frac{( x - 5 )}{5}

a sy m pt o t es \frac{x ^{2} - 1}{x + 5}

What is the domain of f(x)=5(x+4)^2-1 ?
The domain of f(x)=5(x+4)^2-1 is -infinity <x<infinity