What is the critical xsqrt(36-x^2) ?

The critical xsqrt(36-x^2) is x=-6,x=-3sqrt(2),x=3sqrt(2),x=6

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critical xsqrt(36-x^2)

critical points

x 36 - x^{2}

x = - 6, x = - 32, x = 32, x = 6

Solution steps

x 36 - x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 32, x = 32, x = - 6, x = 6

Identify critical points not in

f (x)

domain

Domain of

x 36 - x^{2} : - 6 \leq x \leq 6

All critical points are in domain

x = - 6, x = - 32, x = 32, x = 6

9 t - 4 t^{2}

f (x) = \frac{8 e ^{x}}{1 + e ^{- x}}

f (x) = 7 x^{2}

- 49 - x^{2}

f (x) = cos (- 2 sin^{2} (x^{3}))

What is the critical xsqrt(36-x^2) ?
The critical xsqrt(36-x^2) is x=-6,x=-3sqrt(2),x=3sqrt(2),x=6