What is the range of-sqrt(49-x^2) ?

The range of-sqrt(49-x^2) is -7<= f(x)<= 0

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range of-sqrt(49-x^2)

range

- 49 - x^{2}

- 7 \leq f (x) \leq 0

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

- 49 - x^{2} : - 7 \leq x \leq 7

Extreme Points of

- 49 - x^{2} :

Maximum

(- 7, 0),

Minimum

(0, - 7),

Maximum

(7, 0)

Find the range for the interval

- 7 \leq x \leq 7 : - 7 \leq f (x) \leq 0

Combine the ranges of all domain intervals to obtain the function range

- 7 \leq f (x) \leq 0

f (x) = cos (- 2 sin^{2} (x^{3}))

\frac{2 x}{2 x - 4}

f (x) = \frac{1}{2} x - 4

y = \frac{x ^{4}}{25 - x ^{2}}

f (x) = 12 x