extreme f(x)=((x^2))/(x^2-81)

Lösung

extrempunkte

f (x) = \frac{( x ^{2} )}{x ^{2} - 81}

Maximum (0, 0)

Schritte zur Lösung

f^{'} (x) = - \frac{162 x}{( x ^{2} - 81 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < - 9,

Ansteigend

: - 9 < x < 0,

Absteigend

: 0 < x < 9,

Absteigend

: 9 < x < \infty

Stecke

x = 0

\frac{x ^{2}}{x ^{2} - 81} : 0

Maximum (0, 0)

e x t re m e f (x) = 3 x^{3} - 12 x^{2} + 12 x - 6, 0 \leq x \leq 4

e x t re m e f (x) = x (16 - 41 + 2 x) (\frac{41}{2} - x)

e x t re m e f (x, y) = 3 x - 1.5 x y + 0.5 y^{3}

e x t re m e f (x) = sin (x) \cdot cos (x)

e x t re m e x^{2} + x y + y^{2} + 4 y