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Popular >

derivative of sqrt(x^2+4x)

Solution

\frac{d}{d x} (x^{2} + 4 x)

Solution

\frac{x + 2}{x ^{2} + 4 x}

Solution steps

\frac{d}{d x} (x^{2} + 4 x)

Apply the chain rule:

\frac{1}{2 x ^{2} + 4 x} \frac{d}{d x} (x^{2} + 4 x)

= \frac{1}{2 x ^{2} + 4 x} \frac{d}{d x} (x^{2} + 4 x)

\frac{d}{d x} (x^{2} + 4 x) = 2 x + 4

= \frac{1}{2 x ^{2} + 4 x} (2 x + 4)

Simplify

\frac{1}{2 x ^{2} + 4 x} (2 x + 4) : \frac{x + 2}{x ^{2} + 4 x}

= \frac{x + 2}{x ^{2} + 4 x}

Popular Examples

(dy}{dx}=\frac{2x(y+1))/y

\frac{d y}{d x} = \frac{2 x ( y + 1 )}{y}

derivative of 48

\frac{d}{d x} (48)

derivative of 2/(sqrt(4x+3))

\frac{d}{d x} (\frac{2}{4 x + 3})

y^{^{'}} + (x + 3) y^{2} = 0

derivative of 7x^{1/3}-7x^{-2/3}derivative of

7 x^{\frac{1}{3}} - 7 x^{- \frac{2}{3}}

Frequently Asked Questions (FAQ)

What is the derivative of sqrt(x^2+4x) ?
The derivative of sqrt(x^2+4x) is (x+2)/(sqrt(x^2+4x))
What is the first derivative of sqrt(x^2+4x) ?
The first derivative of sqrt(x^2+4x) is (x+2)/(sqrt(x^2+4x))