What is the derivative of 2/(sqrt(4x+3)) ?

The derivative of 2/(sqrt(4x+3)) is -4/((4x+3)^{3/2)}

What is the first derivative of 2/(sqrt(4x+3)) ?

The first derivative of 2/(sqrt(4x+3)) is -4/((4x+3)^{3/2)}

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\frac{d}{d x} (\frac{2}{4 x + 3})

- \frac{4}{( 4 x + 3 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{2}{4 x + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{4 x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((4 x + 3)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 4 x + 3 ) ^{\frac{3}{2}}} \frac{d}{d x} (4 x + 3)

= - \frac{1}{2 ( 4 x + 3 ) ^{\frac{3}{2}}} \frac{d}{d x} (4 x + 3)

\frac{d}{d x} (4 x + 3) = 4

= 2 (- \frac{1}{2 ( 4 x + 3 ) ^{\frac{3}{2}}} \cdot 4)

Simplify

2 (- \frac{1}{2 ( 4 x + 3 ) ^{\frac{3}{2}}} \cdot 4) : - \frac{4}{( 4 x + 3 ) ^{\frac{3}{2}}}

= - \frac{4}{( 4 x + 3 ) ^{\frac{3}{2}}}

y^{^{'}} + (x + 3) y^{2} = 0

7 x^{\frac{1}{3}} - 7 x^{- \frac{2}{3}}

\int \frac{5}{1 - x ^{2}} d x

y = x^{3} - 5 x, y = 4 x

\int \frac{x ^{2} + 2 x - 3}{x ^{4}} d x

What is the derivative of 2/(sqrt(4x+3)) ?
The derivative of 2/(sqrt(4x+3)) is -4/((4x+3)^{3/2)}
What is the first derivative of 2/(sqrt(4x+3)) ?
The first derivative of 2/(sqrt(4x+3)) is -4/((4x+3)^{3/2)}