What is the solution for (dy}{dx}=\frac{2x(y+1))/y ?

The solution for (dy}{dx}=\frac{2x(y+1))/y is y=-\W(-1/(e^{-c_{1)+x^2}})-1

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(dy}{dx}=\frac{2x(y+1))/y

\frac{d y}{d x} = \frac{2 x ( y + 1 )}{y}

y = - W (- \frac{1}{e ^{- c_{1} + x^{2}}}) - 1

Solution steps

\frac{d y}{d x} = \frac{2 x ( y + 1 )}{y}

Solve Bernoulli ODE:

y = - W (- \frac{1}{e ^{- c_{1} + x^{2}}}) - 1

y = - W (- \frac{1}{e ^{- c_{1} + x^{2}}}) - 1

\frac{d}{d x} (48)

\frac{d}{d x} (\frac{2}{4 x + 3})

y^{^{'}} + (x + 3) y^{2} = 0

7 x^{\frac{1}{3}} - 7 x^{- \frac{2}{3}}

\int \frac{5}{1 - x ^{2}} d x

What is the solution for (dy}{dx}=\frac{2x(y+1))/y ?
The solution for (dy}{dx}=\frac{2x(y+1))/y is y=-\W(-1/(e^{-c_{1)+x^2}})-1