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tangent f(x)=x^2+x,4,\at x=2

解答

切线

f (x) = x^{2} + x, 4, at x = 2

解答

y = 5 x - 4

求解步骤

找到切点:

(2, 6)

计算

f (x) = x^{2} + x

的斜率:

\frac{df ( x )}{d x} = 2 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

找到斜率 m=

5

且穿过

(2, 6)

的直线:

y = 5 x - 4

y = 5 x - 4

作图

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