de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

inverselaplace (e^{-s})/((s+1)^2)

Lösung

inverse laplace transformation

\frac{e ^{- s}}{( s + 1 ) ^{2}}

Lösung

H (t - 1) e^{- t + 1} (t - 1)

Schritte zur Lösung

L^{- 1} {\frac{e ^{- s}}{( s + 1 ) ^{2}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

Wo

H (t)

Heaviside (Schritt) Funktion ist

= H (t - 1) L^{- 1} {\frac{1}{( s + 1 ) ^{2}}} (t - 1)

L^{- 1} {\frac{1}{( s + 1 ) ^{2}}} : e^{- t} t

= H (t - 1) e^{- (t - 1)} (t - 1)

= H (t - 1) e^{- t + 1} (t - 1)

Beliebte Beispiele

integral of-e^{-x}x

\int - e^{- x} x d x

integral from 0 to 10 of f(x)

\int_{0}^{10} f (x) d x

integral of (x^4)/(sqrt(x^5+3))

\int \frac{x ^{4}}{x ^{5} + 3} d x

integral of sqrt(p)+4

\int p + 4 d p

integral of x^3(2-x^2)^{12}

\int x^{3} (2 - x^{2})^{12} d x