What is the integral of sqrt(p)+4 ?

The integral of sqrt(p)+4 is 2/3 p^{3/2}+4p+C

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integral of sqrt(p)+4

\int p + 4 d p

\frac{2}{3} p^{\frac{3}{2}} + 4 p + C

Solution steps

\int p + 4 d p

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int p d p + \int 4 d p

\int p d p = \frac{2}{3} p^{\frac{3}{2}}

\int 4 d p = 4 p

= \frac{2}{3} p^{\frac{3}{2}} + 4 p

Add a constant to the solution

= \frac{2}{3} p^{\frac{3}{2}} + 4 p + C

\int x^{3} (2 - x^{2})^{12} d x

\int 10 x^{9} d x

x \to 0 lim (- 1)

t an g e n t e^{x^{7}}

x^{2} y^{^{''}} + x y^{^{'}} + 4 = 0

What is the integral of sqrt(p)+4 ?
The integral of sqrt(p)+4 is 2/3 p^{3/2}+4p+C