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Popular Calculus >

y^'=e^{-2x}

Solution

y^{^{'}} = e^{- 2 x}

Solution

y = - \frac{1}{2} e^{- 2 x} + c_{1}

Solution steps

y^{'} (x) = e^{- 2 x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int e^{- 2 x} d x

\int e^{- 2 x} d x = - \frac{1}{2} e^{- 2 x} + c_{1}

y = - \frac{1}{2} e^{- 2 x} + c_{1}

Graph

Popular Examples

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Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{-2x} ?
The solution for y^'=e^{-2x} is y=-1/2 e^{-2x}+c_{1}