fläche x=1-y^2,-x-1

Lösung

fläche

x = 1 - y^{2}, - x - 1

\frac{9}{2}

Dezimale

4.5

Schritte zur Lösung

Stelle

y

nach

x = 1 - y^{2}

um:

y = - x + 1, y = - - x + 1

f_{1} (x) = - x + 1

f_{2} (x) = - - x + 1

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

- x + 1 = - - x + 1 : x = 1

- x + 1 = - x - 1 : x = - 3

- - x + 1 = - x - 1 : x = 0

= \int_{- 3}^{0} ∣ f_{1} (x) - f_{3} (x) ∣ d x + \int_{0}^{1} ∣ f_{2} (x) - f_{1} (x) ∣ d x

= \int_{- 3}^{0} - x + 1 - (- x - 1) d x + \int_{0}^{1} - - x + 1 - - x + 1 d x

\int_{- 3}^{0} - x + 1 - (- x - 1) d x = \frac{19}{6}

\int_{0}^{1} - - x + 1 - - x + 1 d x = \frac{4}{3}

= \frac{19}{6} + \frac{4}{3}

Vereinfache

= \frac{9}{2}

\frac{d}{d x} (2 p (x) x)

d er i v a t i v e arctan (\frac{x}{3})

d er i v a t i v e f (x) = x + x + 2

\frac{\partial}{\partial x} (x y (x - 2) (y + 3))

\int x ln (x + 5) d x