What is (d^2)/(dx^2)(2xcos(x^2)) ?

The answer to (d^2)/(dx^2)(2xcos(x^2)) is 2(-6xsin(x^2)-4x^3cos(x^2))

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(d^2)/(dx^2)(2xcos(x^2))

\frac{d ^{2}}{d x ^{2}} (2 x cos (x^{2}))

2 (- 6 x sin (x^{2}) - 4 x^{3} cos (x^{2}))

Solution steps

\frac{d ^{2}}{d x ^{2}} (2 x cos (x^{2}))

\frac{d}{d x} (2 x cos (x^{2})) = 2 (cos (x^{2}) - 2 x^{2} sin (x^{2}))

= \frac{d}{d x} (2 (cos (x^{2}) - 2 x^{2} sin (x^{2})))

\frac{d}{d x} (2 (cos (x^{2}) - 2 x^{2} sin (x^{2}))) = 2 (- 6 x sin (x^{2}) - 4 x^{3} cos (x^{2}))

= 2 (- 6 x sin (x^{2}) - 4 x^{3} cos (x^{2}))

\int_{8}^{14} \frac{y}{y ^{2} - 4 y - 5} d y

y^{^{'}} = e^{- 2 x}

t an g e n t f (x) = x^{2} + 1

7 y^{^{''}} + 5 y^{^{'}} + 7 y = 0

h \to 0 lim (\frac{\frac{4}{2 + h} - 2}{h})

What is (d^2)/(dx^2)(2xcos(x^2)) ?
The answer to (d^2)/(dx^2)(2xcos(x^2)) is 2(-6xsin(x^2)-4x^3cos(x^2))