(\partial)/(\partial x)(ln(t+2cx))

解答

\frac{\partial}{\partial x} (ln (t + 2 c x))

\frac{2 c}{t + 2 c x}

求解步骤

\frac{\partial}{\partial x} (ln (t + 2 c x))

将

c, t

视为常数

使用连锁律:

\frac{1}{t + 2 c x} \frac{\partial}{\partial x} (t + 2 c x)

= \frac{1}{t + 2 c x} \frac{\partial}{\partial x} (t + 2 c x)

\frac{\partial}{\partial x} (t + 2 c x) = 2 c

= \frac{1}{t + 2 c x} \cdot 2 c

化简

\frac{1}{t + 2 c x} \cdot 2 c : \frac{2 c}{t + 2 c x}

= \frac{2 c}{t + 2 c x}

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