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tangent x(x^2-4x+5)^4,\at x=2

解答

切线

x (x^{2} - 4 x + 5)^{4}, at x = 2

解答

y = x

求解步骤

找到切点:

(2, 2)

计算

y = x (x^{2} - 4 x + 5)^{4}

的斜率:

\frac{d y}{d x} = (x^{2} - 4 x + 5)^{4} + 4 x (x^{2} - 4 x + 5)^{3} (2 x - 4)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

找到斜率 m=

1

且穿过

(2, 2)

的直线:

y = x

y = x

作图

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