What is the derivative of 6cos(4x) ?

The derivative of 6cos(4x) is -24sin(4x)

What is the first derivative of 6cos(4x) ?

The first derivative of 6cos(4x) is -24sin(4x)

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\frac{d}{d x} (6 cos (4 x))

- 24 sin (4 x)

Solution steps

\frac{d}{d x} (6 cos (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{d}{d x} (4 x)

= - sin (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 6 (- sin (4 x) \cdot 4)

Simplify

= - 24 sin (4 x)

\int cos^{2} (X) d X

x y^{^{'}} + (1 + x) y = e^{- x} sin (2 x)

d er i v a t i v e f (x) = [(4 x^{2} + 3 x) cos (x)]

\frac{\partial}{\partial x} (x^{2} - 4 x y + 3 y^{2})

\int_{0}^{2 π} e^{i x} d x

What is the derivative of 6cos(4x) ?
The derivative of 6cos(4x) is -24sin(4x)
What is the first derivative of 6cos(4x) ?
The first derivative of 6cos(4x) is -24sin(4x)