What is the derivative of f(x)=[(4x^2+3x)cos(x)] ?

The derivative of f(x)=[(4x^2+3x)cos(x)] is cos(x)(8x+3)-sin(x)(4x^2+3x)

What is the first derivative of f(x)=[(4x^2+3x)cos(x)] ?

The first derivative of f(x)=[(4x^2+3x)cos(x)] is cos(x)(8x+3)-sin(x)(4x^2+3x)

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derivative of

f (x) = [(4 x^{2} + 3 x) cos (x)]

cos (x) (8 x + 3) - sin (x) (4 x^{2} + 3 x)

Solution steps

\frac{d}{d x} (((4 x^{2} + 3 x) cos (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 4 x^{2} + 3 x, g = cos (x)

= \frac{d}{d x} (4 x^{2} + 3 x) cos (x) + \frac{d}{d x} (cos (x)) (4 x^{2} + 3 x)

\frac{d}{d x} (4 x^{2} + 3 x) = 8 x + 3

\frac{d}{d x} (cos (x)) = - sin (x)

= (8 x + 3) cos (x) + (- sin (x)) (4 x^{2} + 3 x)

Simplify

= cos (x) (8 x + 3) - sin (x) (4 x^{2} + 3 x)

\frac{\partial}{\partial x} (x^{2} - 4 x y + 3 y^{2})

\int_{0}^{2 π} e^{i x} d x

\int e^{x^{7}} d x

\int a r cot (x) d x

x \to 0 lim (\frac{( 5 ^{x} - 1 )}{x})

What is the derivative of f(x)=[(4x^2+3x)cos(x)] ?
The derivative of f(x)=[(4x^2+3x)cos(x)] is cos(x)(8x+3)-sin(x)(4x^2+3x)
What is the first derivative of f(x)=[(4x^2+3x)cos(x)] ?
The first derivative of f(x)=[(4x^2+3x)cos(x)] is cos(x)(8x+3)-sin(x)(4x^2+3x)