We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the solution for (e^x+e^{-x})y^'=y^2 ?
- The solution for (e^x+e^{-x})y^'=y^2 is y=-1/(arctan(e^x)+c_{1)}