We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the solution for y^{''}+16y=3sin(4t),y(0)=0,y^'(0)=0 ?
- The solution for y^{''}+16y=3sin(4t),y(0)=0,y^'(0)=0 is y=-(3tcos(4t))/8+3/32 sin(4t)