What is the solution for (d^2y)/(dt^2)-1(dy)/(dt)=0 ?

The solution for (d^2y)/(dt^2)-1(dy)/(dt)=0 is y=c_{1}e^t+c_{2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dt^2)-1(dy)/(dt)=0

\frac{d ^{2} y}{d t ^{2}} - 1 \frac{d y}{d t} = 0

y = c_{1} e^{t} + c_{2}

Solution steps

\frac{d ^{2} y}{d t ^{2}} - 1 \frac{d y}{d t} = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2}

y = c_{1} e^{t} + c_{2}

x^{^{''}} = - 4 x

y^{^{''}} - 12 y^{^{'}} + 36 y = 0, y (0) = 4, y^{^{'}} (0) = 15.45

y^{^{''}} - 12 y^{^{'}} + 36 y = 0, y (0) = 4, y^{^{'}} (0) = 15.46

y^{^{''}} - 6 y^{^{'}} + y = 0

y^{^{''''}} + 5 y^{^{'''}} - 4 y^{^{''}} - 2 y^{^{'}} + \frac{1}{2} y = 0

What is the solution for (d^2y)/(dt^2)-1(dy)/(dt)=0 ?
The solution for (d^2y)/(dt^2)-1(dy)/(dt)=0 is y=c_{1}e^t+c_{2}