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Frequently Asked Questions (FAQ)
What is the solution for y^{''}-12y^'+36y=0,y(0)=4,y^'(0)=15.45 ?
- The solution for y^{''}-12y^'+36y=0,y(0)=4,y^'(0)=15.45 is y=4e^{6t}-8.55e^{6t}t