integral from 0 to 8 of 2sqrt(x)+3

解答

\int_{0}^{8} 2 x + 3 d x

\frac{64 2}{3} + 24

十进制

54.16988 \dots

求解步骤

\int_{0}^{8} 2 x + 3 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{8} 2 x d x + \int_{0}^{8} 3 d x

\int_{0}^{8} 2 x d x = \frac{64 2}{3}

\int_{0}^{8} 3 d x = 24

= \frac{64 2}{3} + 24

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