What is the integral of 1/(x+3+sqrt(x+3)) ?

The integral of 1/(x+3+sqrt(x+3)) is 2ln|sqrt(x+3)+1|+C

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integral of 1/(x+3+sqrt(x+3))

\int \frac{1}{x + 3 + x + 3} d x

2 ln x + 3 + 1 + C

Solution steps

\int \frac{1}{x + 3 + x + 3} d x

Apply u-substitution

= \int \frac{1}{u + u} d u

Apply u-substitution

= \int \frac{2}{v + 1} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{v + 1} d v

Apply u-substitution

= 2 \cdot \int \frac{1}{w} d w

Use the common integral:

\int \frac{1}{w} d w = ln (∣ w ∣)

= 2 ln ∣ w ∣

Substitute back

= 2 ln x + 3 + 1

Add a constant to the solution

= 2 ln x + 3 + 1 + C

What is the integral of 1/(x+3+sqrt(x+3)) ?
The integral of 1/(x+3+sqrt(x+3)) is 2ln|sqrt(x+3)+1|+C