What is the integral of sqrt(7x^8-0^2)(2x^3) ?

The integral of sqrt(7x^8-0^2)(2x^3) is Undefined

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integral of sqrt(7x^8-0^2)(2x^3)

\int 7 x^{8} - 0^{2} (2 x^{3}) d x

Undefined

Solution steps

\int 7 x^{8} - 0^{2} \cdot 2 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int 7 x^{8} - 0^{2} x^{3} d x

7 x^{8} - 0^{2} = 0^{2} (\frac{7 x ^{8}}{0 ^{2}} - 1)

= 2 \cdot \int 0^{2} (\frac{7 x ^{8}}{0 ^{2}} - 1) x^{3} d x

Apply exponent rule:

\frac{a ^{n}}{b ^{n}} = (\frac{a}{b})^{n}

\frac{7 x ^{8}}{0 ^{2}} = (Undefined)^{8}

= 2 \cdot \int 0^{2} (Undefined^{8} - 1) x^{3} d x

= Undefined

Simplify

= Undefined

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What is the integral of sqrt(7x^8-0^2)(2x^3) ?
The integral of sqrt(7x^8-0^2)(2x^3) is Undefined