What is the d/(da)(((a-t^2))/((b*sqrt(x)))) ?

The d/(da)(((a-t^2))/((b*sqrt(x)))) is 1/(bsqrt(x))

What is the first d/(da)(((a-t^2))/((b*sqrt(x)))) ?

The first d/(da)(((a-t^2))/((b*sqrt(x)))) is 1/(bsqrt(x))

\frac{d}{d a} (\frac{( a - t ^{2} )}{( b \cdot x )})

\frac{1}{b x}

Solution steps

\frac{d}{d a} (\frac{( a - t ^{2} )}{( b x )})

Treat

b, t, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{b x} \frac{d}{d a} (a - t^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{b x} (\frac{d a}{d a} - \frac{d}{d a} (t^{2}))

\frac{d a}{d a} = 1

\frac{d}{d a} (t^{2}) = 0

= \frac{1}{b x} (1 - 0)

Simplify

= \frac{1}{b x}

- 12 x

(x^{2} - x)^{3}

\frac{d}{d h} (0.606 \cdot h^{3} + 0.27 \cdot h^{2} + 0.12 \cdot h)

(2 x^{2} - 4 x + 1) (6 x - 5)

ln (2 x^{2})

What is the d/(da)(((a-t^2))/((b*sqrt(x)))) ?
The d/(da)(((a-t^2))/((b*sqrt(x)))) is 1/(bsqrt(x))
What is the first d/(da)(((a-t^2))/((b*sqrt(x)))) ?
The first d/(da)(((a-t^2))/((b*sqrt(x)))) is 1/(bsqrt(x))