What is the derivative of ln^1(+x) ?

The derivative of ln^1(+x) is 1/x

What is the first derivative of ln^1(+x) ?

The first derivative of ln^1(+x) is 1/x

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derivative of

ln^{1} (+ x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln^{1} (x))

Simplify

ln^{1} (x) : ln (x)

= \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= \frac{1}{x}

f (x) = 3 x^{2} - 2 x - 1

\frac{d}{d a} (3 sin^{2} (a) - 2 cos^{2} (a))

\frac{500}{q}

(1 + x^{2})^{\frac{1}{2}}

\frac{d}{d x} (sin (\frac{x}{( y + 1 )}))

What is the derivative of ln^1(+x) ?
The derivative of ln^1(+x) is 1/x
What is the first derivative of ln^1(+x) ?
The first derivative of ln^1(+x) is 1/x