What is the d/(da)(3sin^2(a)-2cos^2(a)) ?

The d/(da)(3sin^2(a)-2cos^2(a)) is 5sin(2a)

What is the first d/(da)(3sin^2(a)-2cos^2(a)) ?

The first d/(da)(3sin^2(a)-2cos^2(a)) is 5sin(2a)

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\frac{d}{d a} (3 sin^{2} (a) - 2 cos^{2} (a))

5 sin (2 a)

Solution steps

\frac{d}{d a} (3 sin^{2} (a) - 2 cos^{2} (a))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (3 sin^{2} (a)) - \frac{d}{d a} (2 cos^{2} (a))

\frac{d}{d a} (3 sin^{2} (a)) = 3 sin (2 a)

\frac{d}{d a} (2 cos^{2} (a)) = - 2 sin (2 a)

= 3 sin (2 a) - (- 2 sin (2 a))

Simplify

= 5 sin (2 a)

\frac{500}{q}

(1 + x^{2})^{\frac{1}{2}}

\frac{d}{d x} (sin (\frac{x}{( y + 1 )}))

\frac{( x + 2 )}{( y - 2 )}

sin (lo g_{10} (1 + x))

What is the d/(da)(3sin^2(a)-2cos^2(a)) ?
The d/(da)(3sin^2(a)-2cos^2(a)) is 5sin(2a)
What is the first d/(da)(3sin^2(a)-2cos^2(a)) ?
The first d/(da)(3sin^2(a)-2cos^2(a)) is 5sin(2a)